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A gas volume `100 cc` is kept in a vessel at pressure `10.4 Pa` maintained at temperature `24^(@)C`. Now, if the pressure is increased to `105Pa`, keeping the temperature constant, then the volume of the gas becomesA. `10cc`B. `100cc`C. `1 cc`D. `1000 cc` |
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Answer» Given `V_(1)=100 mL` `P_(1)=10.4 Pa` `V_(2)=?` `P_(2)=105 Pa` ` P_(1)V_(1)=P_(2)V_(2)` `:. V_(2)=(P_(1)V_(1))/(P_(2))=(105xx100)/(10.4)=10 mL` |
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