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A gas occupies 100.0 mL at `50^(@)C` and I atm pressure. The gas is cooled at constant pressure so that its volume is reduced to 50.0 mL. what is the final temperautre? |
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Answer» Given `V_(1)=100mL` `T_(1)=50^(@)C` `P_(1)=1atm` `V_(2)=50mL` `T_(2)=?` `T_(2)=V_(2)T_(1)//V_(1)=-111.5^(@)C |
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