1.

A gas is found to contain 2.34g of nitrogens and 5.34g of oxygens simplest formulae of the compound is

Answer»

2.34/14= N = 0.167
5.34/16 = O = 0.333

divide MOLES by least amount of moles

N = 0.167/.167 = 1
O = 0.333/.167 = 2

this WAY it can be found by emperical formula.

formula will be NO2



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