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A gas expands by `0.5L` against a constant pressure of `1 atm`. Calculate the work done in joule and calorie. |
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Answer» Work `=- P_(ex) xx` Volume change `= - 1xx 0.5 =- 0.5L atm` `=- 0.5 xx 101.328J =- 50.664J` `0.5L tam =- 0.5 xx 24.20 cal =- 12.10cal` |
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