A gas at a pressure of 5 atm is heated from o° to 546°C and is simul

1.	A gas at a pressure of 5 atm is heated from o° to 546°C and is simultaneously compressed to one third of its original volume. Find the final pressure of the gas.
Answer» Given, P₁ = 5 atm T₁ = 0 + 273 = 273 K T₂ = 546 + 273 = 819 K V₁ = V V₂ = \(\frac{1}{3}\)V P₂ = ? According to ideal gas equation, \(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\) \(\therefore\) P₂ = \(\frac{P_1V_1T_2}{T_1V_2}\) = \(\frac{5\times V\times819}{273\times\frac{V}{3}}\) = \(\frac{5\times V\times819\times3}{273\times V}\) = 45 atm.

A gas at a pressure of 5 atm is heated from o° to 546°C and is simultaneously compressed to one third of its original volume. Find the final pressure of the gas.

Answer»

Given, P₁ = 5 atm

T₁ = 0 + 273 = 273 K

T₂ = 546 + 273 = 819 K

V₁ = V

V₂ = \(\frac{1}{3}\)V

P₂ = ?

According to ideal gas equation,

\(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\)

\(\therefore\) P₂ = \(\frac{P_1V_1T_2}{T_1V_2}\) = \(\frac{5\times V\times819}{273\times\frac{V}{3}}\)

= \(\frac{5\times V\times819\times3}{273\times V}\) = 45 atm.