1.

a gas at a pressure of 5 atm is heated from 0°c to 546°c and simultaneously compressed to 1/3 of its original volume.Hence final pressure is

Answer»

:P1 = 5 atm
T1 = 273 K ;
T2 = (273 + 546) K= 819 K
V1 = V1
V2 = V1/3
Combining the gas laws, we obtain
P1V1÷T1=P2V2÷T2
or P2=P1V1×T2÷V2×T2
=>now SUBSTITUTING value
=>5×V1×819÷V1/3×273
=>5×819×3÷273 ( V1 cancelout with V1)
=>45atm

Hope it will help you!!!


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