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A gas at a pressure of 5.0 atm is heated from `0^(@)C` to `546^(@)C` and simultaneously compressed to one-third of its original volume. Hence, final pressure is:A. 15.0 atmB. 30.0 atmC. 45.0 atmD. `(5)/(9) atm` |
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Answer» Correct Answer - C `(p_(1)V_(1))/T_(1)=(p_(2)V_(2))/(T_(2))rArr(5xxV_(1))/(273)=(p_(2)xxV_(1)/(3))/(819)` `p_(2)=45 " atm"` |
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