1.

A garrison of 120 men has provision for 30 days. At the end of five days, five moremen joined them. How many days can they sustain on the remaining provision?​

Answer»

we KNOW that no. of days is inversely propotional to the provision for MEN

So for 120 men the provision WOULD LAST for 30days. (given) 

Therefore, the provision for 1 men would sustain for. 120 *30 = 3600 days. 

Let after the joining of 5 men (after 5 days) the no of more days the provision would last is x days 

A.t.q 120*30 = 120*5+125*x 

(120*30) - (120*5)= 125x 

120(30-5)=125x 

120 * 25 = 125x 

120 = 5x 

x=120/5 

x= 24 

so the provision would remain for more 24 days.

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