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A galvanometer of resistance `50Omega` is connected to a b attery of 3V alongwith a resistance of `2950Omega` in series. A full scale deflection of 30 division is obtained in the galvanometer in order to reduce this deflection to 20 division. The resistance in sereis. should be:-A. `6050Omega`B. `4450Omega`C. `5050Omega`D. `5550Omega` |
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Answer» Correct Answer - 2 `I_(2)=(3)/(50+2950)prop30I_(g)=(3)/(50+R) prop20` `rArr(50+R)/(50+2 950)=(3)/(2)rArr50+R=4500` `rArrR=4450Omega` |
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