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A galvanometer having a coil resistance of 60 22 shows full scale deflection when a current of 1.0 A passes through it. It can be converted into an ammeter to read currents upto 5.0 A by |
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Answer» So here GIVEN that Rm=20 OHM, Im=0.5A, I=5A, Rs=?Rs=20/[(5/0.5) -1]Rs=20/[10–1], => Rs = 20/9 = 2.22 ohmSo we need to CONNECT a shunt resistance of 2.22 ohm in parallel to the EXISTING 20 ohm , to MAKE an ammeter of (0–5) A.If any questions you have, feel free to comment.Thanks & Regards Deepakmark me brailiest |
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