A galvanometer having a coil of resistance 12 Ω gives full scale def

1.	A galvanometer having a coil of resistance 12 Ω gives full scale deflection for a current of 4 mA. How can it be converted into a voltmeter of range 0 to 24V?
Answer» Given G = 12 Ω, _Ig = 4 x 10^-3A. V = 24V We have, R = \(\frac{V}{I_R}\) - G R = \(\frac{24}{4\times 10^{-3}}\) - 12 R = 5988Ω A resistance of 5988 Ω must be connected in series with galvanometer.

A galvanometer having a coil of resistance 12 Ω gives full scale deflection for a current of 4 mA. How can it be converted into a voltmeter of range 0 to 24V?

Answer»

Given

G = 12 Ω,

_Ig = 4 x 10^-3A.

V = 24V

We have,

R = \(\frac{V}{I_R}\) - G

R = \(\frac{24}{4\times 10^{-3}}\) - 12

R = 5988Ω

A resistance of 5988 Ω must be connected in series with galvanometer.

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A galvanometer having a coil of resistance 12 Ω gives full scale deflection for a current of 4 mA. How can it be converted into a voltmeter of range 0 to 24V?

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