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A galvanometer coil has a resistance of 15 Omega and the meter shows full scale deflection for a current of 4 mA. How will you convert the meter into a voltmeter of range 0 to 6A ? |
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Answer» SOLUTION :Here `R_G = 15 Omega , I_g = 4 mA = 4 XX 10^(-3)A` and ammeter.s rangeI = 6A To convert galvanometer into a ammeter of desired RANGE, we should join a resistance `r_s` in parallel to the galvonometer, where `r_s= (I_g)/(I - I_g) cdot R_G = (4 xx 10^(-3))/(6 - 4 xx 10^(-3)) xx 15 = 10^(-2) Omega = 10 m Omega`. |
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