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A function has the equation Acos3t+Bsin3t.find the valu of the period? |
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Answer» Correct option isC83πab x=acos 3 t∴ dtdx =−3acos 2 tsint, y=asin 3 t∴ dtdx =+3asin 2 tcostThe closed curve is traced as t varies from 0 to 2π∴ x dtdy −y dtdx =3absin 2 tcos 2 t (A)∴ Required area = 21 ∫ 02π (x dtdy −y dtdx )DT = 23ab ∫ 02π sin 2 tcos 2 tdt = 23ab ×4∫ 0π/2 sin 2 tcos 2 tdt = 23ab ×4× 4×21×1 × 2π ( Using Wallis FORMULA). = 83abπ Explanation:please mark me as Brainaliest |
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