A function f(x) has x-intercepts of -3 and -5. What is the constant te

1.	A function f(x) has x-intercepts of -3 and -5. What is the constant term in the function?f(x) = x2 + 8x +
Answer» Constant term in the function is 15 correct answer isf(x) = x² + 8x + 15 please like and accept as best answer 15 is the correct answer x^2+8x+15 = x^2+3x+5x+15=x(x+3)+5( x+3)=( x+3)(x+5)=0; x=-3,-5 15 is the correct answer

A function f(x) has x-intercepts of -3 and -5. What is the constant term in the function?f(x) = x2 + 8x +

Answer»

Constant term in the function is 15

correct answer isf(x) = x² + 8x + 15

please like and accept as best answer

15 is the correct answer

x^2+8x+15 = x^2+3x+5x+15=x(x+3)+5( x+3)=( x+3)(x+5)=0; x=-3,-5

15 is the correct answer