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A frog was at the bottom of an 80 m deep well. It attempted to come out of it by jumping. In each jump, it covered 1.15 m but slipped down by 0.75 m. The number of jumps after which it would be out of the well is:1. 2002. 1983. 2014. 199 |
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Answer» Correct Answer - Option 4 : 199 Given: Depth of the well = 80 m In each jump, the frog covered 1.15 m but slipped down by 0.75 m Calculation: Net distance covered by the frog in one jump = 1.15 – 0.75 = 0.4 m So, total number of jumps = 80/0.4 = 200 But here, after 198 jumps, the distance covered = 0.4 × 198 = 79.2 meters After the 199th jump, the distance covered = 79.2 + 1.15 = 80.35 meters Also, the length of the well = 80 meters. ∴ After the 199th jump, the frog would be out of the well Candidates often make a mistake by taking the number of jumps required as 200. But we had used that calculation only for reference to get an approximate figure of the number of jumps needed. However practically, the frog would be out of the well after the 199th jump only. |
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