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A Fresnel's biprism is usedto form the interference fringes.The distance between the source and the biprism is 20 cms and that between the biprism and the screen is 80 cm. Iflambda = 6563 Å and the separation between the virtual sources is 3.6 mm, then the fringe width is : |
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Answer» `1.82 CM` `LAMBDA = 6563 Å` `BETA = (D)/(d)lambda = 0.0182 cm`. |
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