1.

A freely falling body has a velocity v after covering a height of h , what will b be the velocity after covering the height of 2h? With explanation please...​

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Answer:hi there is your ans

Explanation:Initial speed of the body u=0

Acceleration of the freely falling body  a=g

Velocity of body after covering h distance,  v  

1

​  

=V

Using  v  

1

​  

−u  

2

=2gh

∴  V  

2

−0=2gh

We get  V  

2

=2gh                  ....(1)

LET the total distance COVERED by body to ATTAIN v  

2

​  

=2V be H.

Using  v  

2

​  

−u  

2

=2gH

Or   4V  

2

−0=2gH

Or  4V  

2

=2gH

Or 4(2gh)=2gH

Thus we get  H=4h

Now REQUIRED distance the body needed to fall Δh=H−h

∴  Δh=4h−h=3h


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