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A force `vecF=(3veci+4hatj)N` acts on a 2 kg movable object that moves from an initial position `vecd_(1)=(-3hatij-2hatj)m` to a final position `vecd_(f)=(5hati+4hatj)` m is 6 s. The average power (in watt) delivered by the force during the interval is equal to: |
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Answer» Correct Answer - 8 (Easy) `vecd=vecd_(f)-vecd_(i)=8hati+6hatj` `W=vecF.vecd=24+24=48J` `P_(av)=(W)/(t)=8`watt |
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