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A force of 98 N is just required to move a mass of 45 kg on a rough horizontal surface. Find the coefficient of friction and angle of friction? |
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Answer» F = 48 N,R = 45 x 9.8 = 441N µ =\(\frac{F'}{R}\) = 0.22 Angle of friction θ = tan-1 0.22 = 12°24′ |
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