A force of 98 N acts on a body of mass 10 kg which is at rest. Calcula

1.	A force of 98 N acts on a body of mass 10 kg which is at rest. Calculate 1. Velocity at the end of 5 seconds. 2. Distance traveled by the body in 5 seconds.
Answer» 1. To find the velocity at the end of 5 seconds. We have, F = ma Given, F = 98 N and m = 10 kg ∴ acceleration a = F/m = 98/10 = 9.8 ms^-2 velocity v = u + at Here a = 0, a = 9.8 ms^-2 and t = 5 s ∴ v = 0 + 9.8 × 5 = 49.0 ms^-1 2. To find the distance travelled we have, s = ut + 1/2 at² Here, u = 0, a = 9.8 ms^-2 t = 5 seconds ∴ s = 0 × 5 + 1/2 x 9.8 x (5)² = 122.5 m.

A force of 98 N acts on a body of mass 10 kg which is at rest. Calculate 1. Velocity at the end of 5 seconds. 2. Distance traveled by the body in 5 seconds.

Answer»

1. To find the velocity at the end of 5 seconds.

We have, F = ma

Given, F = 98 N and

m = 10 kg

∴ acceleration a = F/m = 98/10

= 9.8 ms^-2

velocity v = u + at

Here a = 0,

a = 9.8 ms^-2 and

t = 5 s

∴ v = 0 + 9.8 × 5

= 49.0 ms^-1

2. To find the distance travelled

we have, s = ut + 1/2 at²

Here, u = 0,

a = 9.8 ms^-2

t = 5 seconds

∴ s = 0 × 5 + 1/2 x 9.8 x (5)²

= 122.5 m.