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A force of 50 n is inclined to the horizontal at 60 degree obtain its component along x and y? |
| Answer» FORCE and it's componentsExplanation:Force = 50 N ANGLE is with horizontal and 60° ★ Component along x AXIS = F × sin 60° = 50 × √3 / 2 = 25 √3 N ★ Component along y axis = F × COS 60° = 50 × 1 / 2 = 25 N Hope it helps you | |