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A force of 3N acts through moment arm of √2N produced torque 3N_m .then the angle between arm is |
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Answer» 45°Explanation:as we KNOW that; torque=rFsinΦthus; sinΦ=torque/rFsinΦ=1/√2and FINALLY; Φ=sin-¹1/√2Φ=45° |
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