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A force of 2i+3j+4k n acts on a body for 4 sec and produce a displacement of 3i+4j=5k m.The power used is |
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Answer» power=work DONE / time p=F.S/t f.s=2i+3j+4k . 3i+4j+5k = 16+12+20=38 w=38 t=4 p=38/4 =9.5
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