1.

A force of 2i+3j+4k n acts on a body for 4 sec and produce a displacement of 3i+4j=5k m.The power used is

Answer»

power=work DONE / time

p=F.S/t

f.s=2i+3j+4k . 3i+4j+5k

    = 16+12+20=38

w=38

t=4

p=38/4

   =9.5



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