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A force of 12N acts on an object of mass of 4kg in the state of rest for 3s. Calculate the kinetic energy acquired by the object. |
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Answer» ONG>Answer: we KNOW that, F=m×a given that, f=12n m=4kg t=3s. therefore u=0 a=v-u/t=F/m 12/4=3m/s2 v=u+at v=0+3×3=9m/s kE=1/2mv2 ke=1/2×4×(9)2 K.E=2×81=162j. hope it helpful for u |
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