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A force of 10i - 3j + 6k acts on a body of 5 kg and it displace it from 6i + 5j - 3km to 10i – 2j +7km. The work done is (1) 121 J (2) 0 (c) 100 J (4) none of these. |
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Answer» Answer is (1) 121 J W = F.d = (10i - 3j + 6k).(10i – 2j + 7k - 6i - 5j + 3k) = (10i - 3j + 6k).(4i – 7j + 10k) = 40 + 21 + 60 = 121 J |
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