A force of (10hati-3hatj+6hatk)N acts on a body of 5 kg and displaces it from (6hati+5hatj-3hatk)m"to" (10hati-2hatj+7hatk)m. The work done is

A force of (10hati-3hatj+6hatk)N acts on a body of 5 kg and displaces

1.	A force of (10hati-3hatj+6hatk)N acts on a body of 5 kg and displaces it from (6hati+5hatj-3hatk)m"to" (10hati-2hatj+7hatk)m. The work done is
Answer» 100J 0 121J none of these Solution :Here `F=(10hati-3hatj+6hatk)N` `"DISPLACEMENT vector"=vecx=(x_(2)-x_(1))HATI+(y_(2)-y_(1))hatj+(z_(2)-z_(1))hatk` `vecx=(10-6)hati+(-2-5)hatj+(7+3)hatk=4hati-7hatj+10hatk` `"We know that WORK done" =w=vecF.vecs=(10hati-3hatj+6hatk)(4hati-7hatj+10k)` `=40+21+60=121J`