A force is inclined at 60^(@)to the horizontal. If the horizontal component of force is 40N. Calculate the vertical component .

A force is inclined at 60^(@)to the horizontal. If the horizontal comp

1.	A force is inclined at 60^(@)to the horizontal. If the horizontal component of force is 40N. Calculate the vertical component .
Answer» Solution :Let the force be `vec(F)`. Let angle of INCLINATION be `theta` `:.`Horizontal component `F_(H) = F COS theta` Vertical component`F_(v) = F sin theta` Given :`F_(H) = 40 kg . wt.` Angle ` theta = 60^(@)` `F_(H) = F cos 60^(@) = 40 kg wt` . `:. F = (40)/(cos 60^(@)) = (40)/((1)/(2)) = 80 kg wt` Vertical component `F_(v) = F sin theta` ` = 80 sin 60^(@) = 80 xx (sqrt(3))/(2)` `= 40 sqrt(3)` `= 40 xx 1.732 = 69 . 28 ` kg wt `{:("Vertical"),("component"),("of the force"):}} = 69 . 28 `kg wt .