Saved Bookmarks
| 1. |
A force is inclened at `60 ^(@)` to the horizontal . If its horizontal coponent in the horizonal direction is `60N` find themagitude of theforce and its vertical componet. |
|
Answer» Let (F) be the force applied, `theta =60^(00`. Horizontal component of force, `F_(x) =F cos theta` :. 60 =F cos 60^(0) =F xx 1//2` or `F=60 xx 2 =120 N` Verical component of force, `F sin theta =120 sin `60^(0)` `=120 xx sqrt 3 // 2` `=103 .92 N` . |
|