A force F is related to the position of a particle by the relation F = (10x^2) N. The work done by the force when the particle moves from x= 2 m to x = 4 m is

A force F is related to the position of a particle by the relation F =

1.	A force F is related to the position of a particle by the relation F = (10x^2) N. The work done by the force when the particle moves from x= 2 m to x = 4 m is
Answer» `56/3 J` `560J` `560/3 J` `3/560 J` Solution :`W = int_2^4 F dx = int_2^4 10 x^2 dx = [(10 x^3)/(3)]_(2)^(4)` `= 10/3 [4^3 - 2^3] = 10/3 xx 56 = 560/3 J`