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A force F is applied to the initially, stationary cart. The variation of force with time is shown in the figure. The speed of cart at t = 5 s is A. 4B. `0.67`C. `3.75`D. `2` |
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Answer» Correct Answer - B Here `F = 5t^(2)` `f_("max") = mu N = 5N` `a = (5t^(2) - 5)/(10)` `underset(0)overset(v)(int) dv = underset(1)overset(2)(int) (1)/(2) (t^(2) - 1) dt` `v = (1)/(2)[(t^(3))/(3) - t]_(1)^(2)` `v = (2)/(3) m//s` |
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