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A force F is applied on the top of a ring of mass M and radius R placed on a rough horizontal surface. Friction is sufficient to prevent slipping. Find the frictional force acting on the ring. |
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Answer» Solution :`:.alpha=(TAU)/(I)=(F(2R))/(2MR^(2))=(F)/(MR)` Now `F+f=Ma=Mralpha=F` or `f=0`
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