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A force f acts tangentially at the highest point of a disc of mass m kept on a rough horizontal plane. If the disc rolls without slipping, the acceleration of centre of the disc is |
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Answer» eleration of centre of the disc is a = 4F / 3mExplanation:The FORCE F acting on the sphere moves it TOWARDS right.The contact point between force and sphere will slip towards right Thus the static friction( force f shown ) on the sphere will act towards left. LET Radius of the sphere = rLinear acceleration = aSince there is SLIPPING alpha "α"= r a For linear motion F - f = ma ----- (1)Where "f" is the frictional force For rotational motion, torque about center "τ" = Fr+fr = Iα=( 1/2 mr^2 ) a/rF+f= 1/2 ma ---- (2) From (1) and (2) adding, we get 2 F = 3 / 2 ma a= 4F / 3mThus the acceleration of centre of the disc is a = 4F / 3mAlso LEARN moreA particle moving with a velocity of 5 m/s accelerated uniformly with an acceleration of 2 m/s for 10 s. find the displacement in the last second. ?brainly.in/question/3500912 |
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