A force F=(5^i+3^j) newton is applied over a particle which displaces

1.	A force F=(5^i+3^j) newton is applied over a particle which displaces it from its origin to the point r=(2^i−1^j) metre. The work done on the particle is
Answer» A force $F = (5^i + 3^j)$ newton is applied over a particle which displaces it from its origin to the point $r = (2^i - 1^j)$ metre. The work done on the particle is

A force F=(5^i+3^j) newton is applied over a particle which displaces it from its origin to the point r=(2^i−1^j) metre. The work done on the particle is

Answer»

A force $F = (5^i + 3^j)$ newton is applied over a particle which displaces it from its origin to the point $r = (2^i - 1^j)$ metre. The work done on the particle is

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A force F=(5^i+3^j) newton is applied over a particle which displaces it from its origin to the point r=(2^i−1^j) metre. The work done on the particle is

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