A force →F=(3t^i+5^j) N acts on a body whose displacement varies as – InterviewSolution

1.	A force →F=(3t^i+5^j) N acts on a body whose displacement varies as →s=(2t2^i−5^j) m. Work done by this force in t=0 to 2 sec is (in Joule):
Answer» A force $\to F = (3 t^i + 5^j) N$ acts on a body whose displacement varies as $\to s = (2 t^{2}^i - 5^j) m$ . Work done by this force in $t = 0$ to $2 sec$ is (in Joule):

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