A Force →F=−2k [y^i+x^j] N ,where k is constant, acts on a particle moving in the xy plane. Starting from the origin, the particle is taken along the positive x−axis to the point (a,0) and then parallel to y− axis to the point (a,a). The total work done by the force →F on the particle is

A Force →F=−2k [y^i+x^j] N ,where k is constant, acts on a particl

1.	A Force →F=−2k [y^i+x^j] N ,where k is constant, acts on a particle moving in the xy plane. Starting from the origin, the particle is taken along the positive x−axis to the point (a,0) and then parallel to y− axis to the point (a,a). The total work done by the force →F on the particle is
Answer» A Force $\to F = - 2 k [y^i + x^j] N$ ,where $k$ is constant, acts on a particle moving in the $x y$ plane. Starting from the origin, the particle is taken along the positive $x -$ axis to the point $(a, 0)$ and then parallel to $y -$ axis to the point $(a, a)$ . The total work done by the force $\to F$ on the particle is

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A Force →F=−2k [y^i+x^j] N ,where k is constant, acts on a particle moving in the xy plane. Starting from the origin, the particle is taken along the positive x−axis to the point (a,0) and then parallel to y− axis to the point (a,a). The total work done by the force →F on the particle is

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