A force F=(2i^+5j^+k)N is acting on a particle.the particle is first d

1.	A force F=(2i^+5j^+k)N is acting on a particle.the particle is first displaced from(0,0,0) to(2,2,0)m along the path x=y and then from (2,2,0)m to (2,2,2)m along the path x=2m,y=2m. The total work done in the complete path is
Answer» ANSWER: APPLIED the formulae work DONE =force multiply by distance

A force F=(2i^+5j^+k)N is acting on a particle.the particle is first displaced from(0,0,0) to(2,2,0)m along the path x=y and then from (2,2,0)m to (2,2,2)m along the path x=2m,y=2m. The total work done in the complete path is

Answer»

ANSWER:

APPLIED the formulae work DONE =force multiply by distance

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A force F=(2i^+5j^+k)N is acting on a particle.the particle is first displaced from(0,0,0) to(2,2,0)m along the path x=y and then from (2,2,0)m to (2,2,2)m along the path x=2m,y=2m. The total work done in the complete path is

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