1.

A force acts for 10 seconds on a body of mass 10^-2 kg, initially at rest, after which the force ceases to act. The body traverses 0.5 m in the next 5 seconds. The magnitude of the force is :(a) 9.8 N (b) 98 N (c) 10^-2 N (d) 10^-4 NAligarh Muslim University +2 Science/Diploma Entrance Test - 2018-19

Answer»

Let the ACCELERATION be a

so, using second equation of motion we have

S= ut +1/2 at^2

here ,
t=10sec
u=0
and s=0.5m


so,

0.5 = 1/2 × a × 100
so,
a= 1/100 m/sec^2


now F=ma

so , F = 10^-2 ×10^-2


so , F will be 10^-4 N

option c is CORRECT


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