Saved Bookmarks
| 1. |
A force acts for 0.2 sec on an object having mass 1.4 kg initially at rest.the force stops to act but objects moves through 4m in the text 2 seconds find the magnitude of the force |
|
Answer» Initial velocity(u)=0 Final velocity(v)=? TIME Object moves after force stops(t)=2 s Distance(s)=4 m v=s/t v=4/2=2 m/s Time force acts on object(t')=0.2 s Mass(m)=1.4 kg Acceleration(a)=? v=u+at 2=0+a×0.2 2/0.2=a 10 m/s²=a F=ma F=1.4×10 F=14 Newton I hope it help you.. Plzzz MARK me as BRAINLIEST |
|