A force acts for 0.2 sec on an object having mass 1.4 kg initially at

1.	A force acts for 0.2 sec on an object having mass 1.4 kg initially at rest. The force stops to act but the object moves through 4m in the next 2 sec. Find the magnitude of the force? (Ans: 14 N )
Answer» Answer ⇒ 14 N. Solution ⇒ As per as the question, the force has stopped ACTING, thus, the object will MOVE with constant velocity. Given, Distance covered = 4 m. Time taken = 2 seconds. ∵ Velocity = Distance/Time ∴ V = 4/2 = 2m/s Now, Time = 0.2 seconds. Using the First equation of motion, a = (v-u)/t A = (2 - 0)/0.2 A = 10 ms⁻² Now, Using the Newton's second law, Force = mass × acceleration. ∴ Force = 1.4 × 10 ⇒ Force = 14 N Hence the magnitude of the force is 14 N. Hope it helps.

A force acts for 0.2 sec on an object having mass 1.4 kg initially at rest. The force stops to act but the object moves through 4m in the next 2 sec. Find the magnitude of the force? (Ans: 14 N )

Answer»

Answer ⇒ 14 N.

Solution ⇒

As per as the question, the force has stopped ACTING, thus, the object will MOVE with constant velocity.

Given, Distance covered = 4 m.

Time taken = 2 seconds.

∵ Velocity = Distance/Time

∴ V = 4/2

= 2m/s

Now, Time = 0.2 seconds.

Using the First equation of motion,

a = (v-u)/t

A = (2 - 0)/0.2

A = 10 ms⁻²

Now, Using the Newton's second law,

Force = mass × acceleration.

∴ Force = 1.4 × 10

⇒ Force = 14 N

Hence the magnitude of the force is 14 N.

Hope it helps.

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A force acts for 0.2 sec on an object having mass 1.4 kg initially at rest. The force stops to act but the object moves through 4m in the next 2 sec. Find the magnitude of the force? (Ans: 14 N )

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