1.

a force 10N acts on a block ob mass 10kg at an angle of 60 displaces it 5meter calculate work (cas 60=1/2​

Answer»

Step-by-step explanation:

คɴᎦᴡєя

☆ɢɪᴠᴇɴ :-

☛juA force 10 N acts on a BLOCK af MASS 10 KG at an angle of 60° displaces it 5 metre. (cos 60° = ½)

☆ ᴛᴏ ғɪɴᴅ :-

☛What is the work.

☆ғᴏʀᴍᴜʟᴀ ᴜsᴇᴅ :-

WorkDone=FsCosθ

where,

☘F = Force

☘s = Displacement

☘θ = Angle between applied force and displacement.ғɪsʜ

sᴏʟᴜᴛɪᴏɴ :-

ɢɪᴠᴇɴ:

Force = 10 N

Displacement = 5 m

According to the question by USING the formula we get,

[tex]\sf Work\: Done =\: Fs\: Cos\thetaWorkDone=FsCosθ[/tex]

As We know that\theta =\: \dfrac{1}{2}θ=21\sf Work\: Done =\: {\cancel{10}} \times 5 \times \dfrac{1}{\cancel{2}}WorkDone=10×5×21\sf Work\: Done =\: 5 \times5WorkDone=5×5\therefore\sf\mathfrak{\pink{Work\: Done =\: 25\: J}}∴WorkDone=25J


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