1.

A. For the circuit shown in the given picture, Calculate i) equivalent resistance ii) Current

Answer»

From the circuit, Resistors of resistance 5 and 10 are CONNECTED in parallel.So their EFFECTIVE resistance is given by 1/R eq=1/R1+1/R2R eq=R1 R2/R1+R2So R eq = 5×10/5+10= 3.33This R eq is connected with 7 in series,So total effective resistance is 7+3.33= 10.33Current = V/Total effective resistanceCurrent=6/10.33=0.58 A



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