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A football is kicked at an angle of `30^(@)` with the vertical, so if the horizontal component of its velocity is `20 ms^(-1)`, determine its maximum height. |
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Answer» Given, `theta = 30^(@)` Horizontal component of velocity `= u sin 30^(@) = 20 ms^(-1)` `u = (20)/(sin 30^(@)) = (20)/(1//2) = 40 ms^(-1)` Therefore, maximum height, `H = (u^(2) cos^(2) 30^(@))/(2g) = ((40)^(2))/(2 xx 9.8) xx ((sqrt(3))/(2))^(2) = 61.22 m` |
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