A foolball at 25^(@)C has 0.5 mole air molecules . calculate the internal energy of air in the ball.

A foolball at 25^(@)C has 0.5 mole air molecules . calculate the inter

1.	A foolball at 25^(@)C has 0.5 mole air molecules . calculate the internal energy of air in the ball.
Answer» Solution :The INTERNAL energy of ideal GAS `=3/2` NkT. The number of air molecules is given in terms of number of moles so, rewrite the EXPRESSION as follows: `U=3/2muRT` Since `Nk=muR. "Here"mu` is number of moles. Gas CONSTANT `R=8.31 J/("MOL")K` Temperature`T=273+27^(@)C=300K` `U3/2xx0.5xx8.31xx300=1869.75J` This is approximately equivalent to the kinetic energy of a man of 57 kg runinf with a speed of 8 `ms^(-1)`