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A flywheelof mass 25kg has a radius of 0.2 m. What force should be applied to the rim so that it acquires an angular acceleration of5rads^(-2)? |
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Answer» Solution :The MI of the FLYWHEEL= 1/2`Mr^2` =1/2`TIMES` 25 `times(0.2)^2` = 1/2 TORQUE `tau`= `Ialpha`=1/2 `times`5 |
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