1.

A flywheelof mass 25kg has a radius of 0.2 m. What force should be applied to the rim so that it acquires an angular acceleration of5rads^(-2)?

Answer»

Solution :The MI of the FLYWHEEL= 1/2`Mr^2`
=1/2`TIMES` 25 `times(0.2)^2` = 1/2
TORQUE `tau`= `Ialpha`=1/2 `times`5


Discussion

No Comment Found