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A flywheel used to prepare earthenware pots is set nto rotation at 100rpm. It is in the form of a disc of mass 10 kg and radius 0.4 m. A lump of clay (to be to taken equivalent to a particle ) of mass 1.6 kg falls on it and adheres to it at a certain distance x from the centre. Calculate x if the wheel now rotates at 80 rpm

Answer»

Explanation:Moment of INERTIA of flywheel = MR^2/2I1 = 10 x 0.16 /2I1 = 0.8 kgm2w1 = 100 rpm I2 = I1 + mx^2w2 = 80 rpmaccording to law of conservation of angular momentum,I1w1 = I2w20.8 * 100 = (0.8 + 1.6x^2) * 80 CALCULATING the above,1.6x^2 = 0.2Hence,x = 1/2(ROOT 2)x = 0.35 m



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