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a fixed amount of dry air at temperature of 27degree celsius is compressed to 1/9 of its original volume.its final temperature is?(gamma=1.5) a.627degree celsius b.600degree celsius c.158 degree celius d.527 degree celsius plz explain with solution |
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Answer» t dry AIR as an ideal gas.Volume = V1 T1 = 300 Kelvin Pressure = P1V2 = V1 / 9 γ = ratio of specific heats = 1.5 T2 = ? P2 = ?number of moles n is fixed. P1 V1 / T1 = P2 V2 / T2 P1 V1 / 300 = P2 (V1 /9) / T2 => T2 = 33.33 P2 / P1 Is the gas compressed adiabatically and/or SUDDENLY ? with no energy exchanged between the SYSTEM and the environment ? It has to be mentioned whether it was an ISOBARIC compression or adiabatic compression. Otherwise the final pressure is to be mentioned. T2 = 300 * √9 = 900⁰K = 627⁰ C |
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