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A first order reaction has a rate constatn `1.15 xx10^(-3) s ^(-1).` How long will 5 g of this reactant take to reduce to 3 g ? |
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Answer» Rate constant `[k] =1.15xx10^(-3) s^(-1)` initial amount `[R]_(0)=5g,` Final a amount `[R]=3g` `t=(2.303)/(R) log ""([R]_(0))/(R)` `=(2.303)/((1.15xx10^(-3) s^(-1)))log"" ((5g)/(3g))=(2.303)/([1.15xx10^(-3) s^(-1)]) [log 5- log 3]` `=(2.303)/(1.15xx10^(-3) s^(-1))(0.6990-0.4771)=2.0 xx10^(3)xx 0.2219 s=443.8s` Time `=444s.` |
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