Saved Bookmarks
| 1. |
A field of strenght `5 xx 10^(4)//pi` ampere turns`//`meter acts at right angles to the coil of `50` turns of area`10^(-2) m^(2)`. The coil is removed from the field in `0.1` second. Then the induced `e.m.f` in the coil isA. `0.1 V`B. `0.2 V`C. `1.96 V`D. `0.98 V` |
|
Answer» Correct Answer - A `B = mu_(0) H = (mu_(0) xx 5 xx 10^(4))/(pi)` `e = (NBA)/("time") = (50 xx 2 xx 10^(-2) xx 10^(-2))/(0.1) = 0.11` |
|