A field is in the form of a trapezium. Its area is 1586 m2 and the dis

1.	A field is in the form of a trapezium. Its area is 1586 m2 and the distance between its parallel sides is 26 m. If one of the parallel sides is 84 m, find the other.
Answer» Given Let length of parallel sides be 84cm and y cm Area of trapezium = 1586 cm² Let Height (h) = 26 cm We know that area of trapezium is \(\frac{1}{2}\)× (sum of parallel sides) × height Therefore Area of trapezium is \(\frac{1}{2}\)× (84 + y) × 26 =1586 cm². \(\therefore \frac{1}{2}\)× (84 +y) × 26 = 1586 ⇒ (84 + y) × 13 =1586 ⇒ 84 + y = \(\frac{1586}{13}\) ⇒ y = 122 - 84 = 38 ∴ Length of the other parallel side is 38 cm.

A field is in the form of a trapezium. Its area is 1586 m2 and the distance between its parallel sides is 26 m. If one of the parallel sides is 84 m, find the other.

Answer»

Given

Let length of parallel sides be 84cm and y cm

Area of trapezium = 1586 cm²

Let Height (h) = 26 cm

We know that area of trapezium is \(\frac{1}{2}\)× (sum of parallel sides) × height

Therefore Area of trapezium is \(\frac{1}{2}\)× (84 + y) × 26 =1586 cm².

\(\therefore \frac{1}{2}\)× (84 +y) × 26 = 1586

⇒ (84 + y) × 13 =1586

⇒ 84 + y = \(\frac{1586}{13}\)

⇒ y = 122 - 84 = 38

∴ Length of the other parallel side is 38 cm.