1.

A father is 3 times as old his son.after 5 years his age is 2 and a dual times as old as his son.represent this situation algebrically

Answer»

Let the age of the son be X, then father's age is 3(x).

after five years, son's age BECOMES (x+5) and father's age becomes 2(x+5) + 2.

Father's age can also be TAKEN as 3(x) + 5.

So, [ 3(x) + 5 ] = 2(x+5) + 2


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